4(2x-3)+4^2-6x=0

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Solution for 4(2x-3)+4^2-6x=0 equation: 



4(2x-3)+4^2-6x=0

We add all the numbers together, and all the variables

-6x+4(2x-3)+16=0

We multiply parentheses

-6x+8x-12+16=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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